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【OG20-P175-187题】
There are 8 teams in a certain league and each team plays each of the other teams exactly once. If each game is played by 2 teams, what is the total number of games played?
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一个社团里有8个队,每个队只和其他队玩一次游戏。问如果2个队玩一种游戏,那么可以玩多少种游戏
C(2,8)=8*7/2=28
题目讨论 (6条评论)

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susan0424
n=8,r=2,公式=n!/r!(n-r)!=8!/2!(6!)=8*7/1*2=28
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0 回复 2022-02-03 17:39:52
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贾思敏
没有说different啥的,用组合C来算
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0 回复 2021-09-24 16:49:20
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emily666
组合!
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0 回复 2020-03-12 18:48:14
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Jerry W
就是要理解题意,就是指两个人才能一起玩这个游戏
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0 回复 2019-05-19 15:48:14
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Jessica要上720
2个队玩一种游戏,其实就是看总共有多少种分队的可能性。 2个队一组,无关顺序,所以是组合,就是C(2,8)
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0 回复 2019-05-10 19:31:58
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571661zxzq回复Jessica要上720
是 c(8,2)
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0 回复 2020-08-15 02:37:19
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Jesselic
1-4/8*3/7*2/6=13/14
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0 回复 2018-10-01 15:13:16