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【OG20-P292-442题】
The hypotenuse of a right triangle is 10 cm. What is the perimeter, in centimeters, of the triangle?
(1) The area of the triangle is 25 square centimeters.
(2) The 2 legs of the triangle are of equal length.
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题干:设两直角边是a,b,斜边是c。c=10,a^2+b^2=100
条件1:ab=50→(a-b)^2=0→a=b=5√2,充分
条件2:a=b=5√2,充分
题目讨论 (4条评论)

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贾思敏
做条件一的时候有点卡壳,其实就是给出了a^2+b^2=100, ab=50即2ab=100,所以(a-b)^2=0,也就是说a=b,就是ab=a^2=b^2=50,所以a=b=5倍根号下2,那么C=a+b+c的值就可以求出来了 条件二:a=b的话,就是2a^2=100,a=b=5倍根号下2,同理,周长可以求出来。
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0 回复 2021-10-04 19:27:53
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kikig
x^2+y^2= 100 (Pyth Theorem).....1) 2xy=100.........................2) Adding 1) and 2) (x+y)^2= 200 or x+y=10 sqroot 2 (Hence statement 1 is sufficient) or Perimeter = x+y+10 = 10(1+sq.rt2) Statement 2. 2x^2=100; x=5 sqrt2 Perimeter = 10 (1+sqrt2)..(Hence, statement 2 is sufficient) As both statements are sufficient. Hence, D
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0 回复 2019-12-21 09:01:51
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cbc021
可以从毕达哥拉斯定理(勾股定理)的英文版熟悉直角三角形相关的英文词汇: Right triangles obey the Pythagorean theorem: the sum of the squares of the lengths of the two legs is equal to the square of the length of the hypotenuse: a^2 + b^2 = c^2, where a and b are the lengths of the legs and c is the length of the hypotenuse. 条件1: 不妨假设直角边分别为x、y,则由题意和条件可得: x^2+y^2=100 xy=50 欲求x+y+10=? 即求x+y=? 而x+y=sqr((x+y)^2)=sqr(x^2+y^2+2xy)=sqr(200) 故可以得到唯一确定的三角形周长,充分 条件2显然 故选D
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0 回复 2018-02-21 13:16:59
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Jaris+
注意是直角三角形
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0 回复 2017-11-26 11:22:46