雷哥网GMAT-【OG20-P286-380题】If the positive integer n is added to each of the _OG17新题

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【OG20-P286-380题】

If the positive integer n is added to each of the integers 69, 94, and 121,what is the value of n ?

(1) 69+ n and 94 + n are the squares of two consecutive integers.

(2) 94 + n and 121 + n are the squares of two consecutive integers.

A

Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
分析A选项
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B

Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
分析B选项
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C

BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
分析C选项
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D

EACH statement ALONE is sufficient.
分析D选项
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E

Statements (1) and (2) TOGETHER are NOT sufficient.
分析E选项
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当前版本由 Helen 更新于2018-09-21 17:38:30 感谢由 Helen 对此题目的解答所做出的贡献。

条件1:69+n=x^2,94+n=(x+1)^2解得x=12,n=75，充分
条件2:94+n=y^2,121+n=(y+1)^2解得y=13,n=75，充分

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373961gg

are the squares of two consecutive integers--> 为两个连续整数各自的平方

2 0 回复 2020-07-17 12:04:17
kikig

From statement one, we can say that for some positive integer x, 69 + n = x^2 and 94 + n = (x + 1)^2. Let’s subtract the first equation from the second equation: (94 + n) - (69 + n) = (x + 1)^2 - x^2

0 0 回复 2019-12-18 16:58:49
phylliskong38

2 unknown 2 equations ---> solvable

0 0 回复 2018-08-28 22:46:00
Adam.W

1)69+n=a^2 94+n=(a+1)^2 上下相减，a=12, n=75 充分 2) 同样的方法 94+n=b^2 121+n=(b+1)^2 上下相减， b=13, n=75 充分

1 0 回复 2018-02-25 21:53:03