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Set S consists of five consecutive integers, and set T consists of seven consecutive integers. Is the median of the numbers in set S equal to the median of the numbers in set T ?
(1) The median of the numbers in set S is 0.
(2) The sum of the numbers in set S is equal to the sum of the numbers in set T.
分析A选项
分析B选项
分析C选项
分析D选项
分析E选项
解:因为ST都是有连续的整数构成集合,所以S=(a,a+1,a+2,a+3,a+4); T=(b,b+1,b+2,b+3,b+4,b+5,b+6)
条件一说:S的中位数是0,只能得出a=-2,不能判断T中B的值;
条件二说:S的数值值和等于T得数值值和,只能列出5a+10=7b+21,不能判断中数是否相等;但是将两个条件联立,发现可以求出B的值,这样就可以判断两个集合的中位数是否相
小良冠二郎
错选b,动手吧废材,用笔运算才能保证正确
168433ykxxz
为什么b不行? S = { a-2 a-1 a a+1 a+2 } T = { b-3 b-2 b-1 b b+1 b+2 b+3 } 根据条件二可知 5a=7b,那不是只有a和b为0的时候等式才成立吗?所以单条件二不是就满足了吗?
168433ykxxz
为什么b不行?根据条件二可知 5a=7b,那不是只有a和b为0的时候等式才成立吗?所以单条件二不是就满足了吗?
Hamlin回复168433ykxxz
a=7,b=5呢
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2023-01-05 15:05:30
987566z
S = { a-2 a-1 a a+1 a+2 } T = { b-3 b-2 b-1 b b+1 b+2 b+3 } (1) a=0 (2) 5a = 7b
283740ph
连续整数的中位数=平均数
虫0515
错选了B,以为和相等元素个数不等,所以平均数不相等,所以(等差数列)中位数不相等,没有考虑和可能是零的情况。
送我上700回复虫0515
5a=7b我想了半天a怎么可能等于b之道看到你的评论
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2022-03-06 23:10:31
Arizhang
数列里可能会有负数
LISA保佑我上700
我怎么觉得应该选B。S=(a,a+1,a+2,a+3,a+4); T=(b,b+1,b+2,b+3,b+4,b+5,b+6),问a+2是否等于b+3?条件二:5a+10=7b+21 即5(a+2)=7(b+3),所以a+2肯定不可等于b+3.efficient 这样哪错了....
LISA保佑我上700回复LISA保佑我上700
喔 我知道了 a+2和b+3还可以都等于0
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2020-07-27 10:34:41
冲他丫的回复LISA保佑我上700
哎 我也是直接就选了
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2021-11-02 21:26:22
180721qxbb回复LISA保佑我上700
也不只是0,还有a+2=7 -> a=5, b+3=5 -> b=2
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2022-07-17 19:00:50
夏夏夏筱染
条件二反例:a=7,b=5,两个集合元素和是一样的
夏夏夏筱染回复夏夏夏筱染
b=2,打错了
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2019-08-31 10:46:16
夏夏夏筱染回复夏夏夏筱染
a=5
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2019-09-03 14:18:34
Kath1230
遇到five consecutive integers, 就要懂得会把它设置成a, a+1, a+2, a+3, a+4 seven consecutive integers. 就要懂得把它设置成b, b+1, b+2, b+3, b+4, b+5, b+6 第一个条件能求出a 第二个条件能有a和b的关系式子 联立可以求出b,那么就可以知道中位数是否相等
Adelaz
把范围限制到和为零了,没想到其他情况
我要700回复Adelaz
+1
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2018-04-01 20:05:09
桃总漏了
不只有0这种情况啊,设集合1中位数是x,集合2中位数是y,只要5x=7y,sun就相等。0是特殊情况。
ssccvv00回复桃总漏了
integers
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2018-11-12 14:20:24
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