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If ab ≠ 0 and points (-a, b) and (-b, a) are in the same quadrant of the xy-plane, is point (-x, y) in this same quadrant?
(1) xy > 0
(2) ax > 0
分析A选项
分析B选项
分析C选项
分析D选项
分析E选项
(-a,b)(-b,a)在同一个象限,问(-x,y)是否也在这个象限?
xy>0;
ax>0
由于(-a,b)(-b,a)在同一个象限,所以ab>0,且这两点可能在第二或者第四象限内;
条件1.只能说明(-x,y)可能在第二象限,也可能在第四象限,所以不充分;
条件2. ax>0,明显不充分;
但是两个条件联立,可以发现当ax>0时,(-x,y)一定和(-a,b)(-b,a)在同一个象限内
XiaoningChan
(-a,b)和(-b,a)在同一象限时,两者横纵坐标的正负号一致,故ab>0,-a与b异号,这两个坐标可能在第二或第四象限,故要想让(-x,y)与(-a,b)和(-b,a)在同一象限,除了要保证xy>0,还要保证x与a同号。
兔小黄
ab>0这个是怎么推出来的,做题时完全没想到
leon小恶魔回复兔小黄
(-a, b) and (-b, a) are in the same quadrant of the xy-plane:那么-a和-b是同正或同负,a和b同正或同负,得出ab>0
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2022-11-26 18:44:23
leon小恶魔
由题目得出 ab>0 联立(1) xy > 0 和 (2) ax > 0的条件的得出:ay>0,再一步by>0 ,那么x和a同正负,y和b同正负,那么(-x,y)和(-a,b)必定在同一象限
1229394ifpm
题目 两个点 同一个 象限------ a,b 同号 同正同负 所以可以确定不是第二就是第四。 条件一, 得出 xy 这个点不是第二就是第四 无法确定 条件二, ax大于零得出 a x 同号 但是不知道y 所以不行。 1+2 xy 在第二第四象限 而且 x 和 a (b)同号 所以 充分
Litchichi
主要就是确认 a, b, x, y 的正负号,因为在题干中已经给出 a, b 的关系,因此,在确认(-x, y) 是否与 (-a, b)及(-b, a)在同一象限,则需要确认 x, y 的正负号与 a, b 的正负号的关系,才可能确认结果,而无论是条件1或条件2,单独来看,均无法实现 x, y, a的正负号关系,所以,只能选 C,可加上题干给出的 a 和 b 的正负号关系,再加上两个条件给出的 x, y, 和 a 的正负号关系,就能推出结果。
catontheroof
https://www.manhattanprep.com/gmat/forums/if-ab-does-not-equal-zero-t2975.html
Kath1230
头好晕看这道题
月冷隐回复Kath1230
你考了吗?在很多解析里都看到你留言,哈哈。
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2019-05-23 04:49:52
拽mat
注意CD的区别
OoO
审题啊 问题是is point (-x, y) in this same quadrant? 注意限定词this 则一定要判断(-x,y)在一个确定的象限且和(-a,b),(-b,a)一致 而不是只判断它在同一个象限
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