题库搜索>问题求解PS-13083
If d=123∗57 is expressed as a terminating decimal, how many nonzero digits will d have?
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D=1/(2*5*2*5*2*5*5*5*5*5)=1/625000
=0.0000016
s所以非零的位数是：2位：1 和6
rhetoric
别忘了是用1除以
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2022-10-30 23:15:06
ziqi
1除以5的4次方
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2022-07-07 16:00:50
268948hjpc
乘以2^4/2^4, 最后化简后=2^4/10^7。不要硬算，很麻烦的。
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2022-04-05 08:03:17
268948hjpc
乘以2^4/2^4, 最后化简后=2^4/10^7
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2022-04-05 08:01:27
229813acby
这句话nonzero digits will d have?没读懂，以为是问小数点后有几位啊啊啊
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2022-02-22 12:01:20
223252wgwm
2×5=10 所以2的指数和5的指数取最小的，是可以变成零的，不算非零数位 分子分母同×某数，分数大小不变的！ 所以分子分母同×2（4），分母都是000，分子成了16，就是非零数位
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2021-09-20 15:58:45
leaeaead
分享D= 1 1 1
———— = —————— = ——————
2^3*5^7 2^3*5^3*5^4 10^3*5^4
上下同乘以 2^4，则
2^4 16
D= ———————— = ————— = 0.0000016 ， 所以 非零的位数是：2位：1 和6
10^3*5^4*2^4 10^7
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2018-04-23 18:17:20
273408xgm回复 leaeaead
為什麼上下同乘以 2^4
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2019-12-22 16:08:30
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