题库搜索>问题求解PS-13083
If d=123∗57 is expressed as a terminating decimal, how many nonzero digits will d have?
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D=1/(2*5*2*5*2*5*5*5*5*5)=1/625000
=0.0000016
s所以非零的位数是:2位:1 和6
rhetoric
别忘了是用1除以
ziqi
1除以5的4次方
268948hjpc
乘以2^4/2^4, 最后化简后=2^4/10^7。不要硬算,很麻烦的。
268948hjpc
乘以2^4/2^4, 最后化简后=2^4/10^7
229813acby
这句话nonzero digits will d have?没读懂,以为是问小数点后有几位啊啊啊
223252wgwm
2×5=10 所以2的指数和5的指数取最小的,是可以变成零的,不算非零数位 分子分母同×某数,分数大小不变的! 所以分子分母同×2(4),分母都是000,分子成了16,就是非零数位
leaeaead
D= 1 1 1 ———— = —————— = —————— 2^3*5^7 2^3*5^3*5^4 10^3*5^4 上下同乘以 2^4,则 2^4 16 D= ———————— = ————— = 0.0000016 , 所以 非零的位数是:2位:1 和6 10^3*5^4*2^4 10^7
273408xgm回复 leaeaead
為什麼上下同乘以 2^4
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2019-12-22 16:08:30
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