题库搜索>问题求解PS-13289
A certain characteristic in a large population has a distribution that is symmetric about the mean m. If 68 percent of the distribution lies within one standard deviation d of the mean, what percent of the distribution is less than m + d ?
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某一特性在大人口基数的条件下具有关于平均值M对称的分布,如果68%分布于平均值的一个标准偏差D内,那么分布于小于M+D的概率是多少?
The distribution is symmetric, (因为分布是对称的)
so (所以)
50% of the distribution is less than M (有50%的分布是小于平均值M的)
and (并且)
the distribution between M and M+D is half in one D, (在M与M+D之间的分布是一个标准偏差D内的一半)
68%/2 = 34% of the distribution lies between M and M+D. (即68%/2 = 34%分布于M与M+D之间)
so(所以)
50% + 34% = 84% of the distribution is less than M+D (50% + 34% = 84%分布于小于M+D)
662352yo
题目理解错了，苦思冥想为什么没有我的选项。来回看，来回想，结果花了4分钟才做出来。啊！
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2022-12-19 16:43:16
JoeyLau
正态分布
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2021-09-12 15:35:21
308381xsis
什么是“If 68 percent of the distribution lies within one standard deviation d of the mean,”？ 是D 到-D 的距离是68%吗？
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2021-02-25 11:30:19
Ariadne
画一个钟形线，在50%左和右，分别标出34%的区域，要去找出m+d，那就是50+34的左边所有区域即为84%
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2019-05-04 22:03:37
ninielisa
看不懂
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2017-11-13 15:33:52
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80.3%
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