题库搜索>问题求解PS-13397
Mary passed a certain gas station on a highway while traveling west at a constant speed of 50 miles per hour. Then, 15 minutes later, Paul passed the same gas station while traveling west at a constant speed of 60 miles per hour. If both drivers maintained their speeds and both remained on the highway for at least 2 hours, how long after he passed the gas station did Paul catch up with Mary?
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180雷豆
我有更好的解析 
暂无雷哥网文字解析
0*x-50(x+0.25)=0
x= 1.25 hour= 1hr 15 min
212284daal
gmatclub上很神的一种解法 Mary passes gas station and travels at 50 mph for 15 minutes So, Mary drove for 1/4 hours Distance traveled = (time)(speed) = (1/4)(50) = 50/4 = 12.5 miles Paul passes the same gas station and travels at 60 mph IMPORTANT: At this point, Paul is 12.5 miles behind Mary. However, since Paul is traveling 10 mph FASTER than Mary, the gap between them SHRINKS at a rate of 10 mph. So, at this point, we need to determine the time it takes for the 12.5 mile gap to shrink to zero. Time = (distance)/(speed) = 12.5/10 = 1.25 hours = 1 hour 15 mins = D Cheers, Brent
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2022-03-08 18:07:10
不上740不改名
为什么用15mile的距离差值求解是算不出来的？
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2018-05-27 11:18:38
默默哒
路程=时间X速度 追击问题Paul和Mary总共走的的路程是相等的 设Paul用了t小时，则Mary用了t+1/4小时 （1/4 = 15/60） 60t=50（t+1/4), t=4/5=1小时15分钟
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2017-10-04 09:17:43
eve1011回复默默哒
请问，如果我设mary用时t小时，paul就是t-1/4 小时。路程相等不就是 50t＝(t-1/4)60 t= 3/2 不应该选e吗？
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2017-10-19 15:36:12
QY回复默默哒
同问
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2017-11-20 15:13:19
啦啦真的很努力回复 eve1011
如果用两个人的路程差算的话还要减去pual到达gas station的15min
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2018-07-24 16:17:59
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