题库搜索>问题求解PS-13470
The figure above represents a system of roads along which traffic flows in the direction indicated by the arrows. If the traffic were to split evenly at each fork of the road system, what percent of the traffic entering fork C would exit at Y?
分析A选项
分析B选项
分析C选项
分析D选项
分析E选项
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当前版本由 slong827 更新于2017-06-15 10:41:29 感谢由 slong827 对此题目的解答所做出的贡献。从c进从y出的概率
C进一共有：3+5=8条路走
从y出的有：7条路
所以7/8=87.5%
当前版本由 471788hzsl 更新于2020-06-18 01:53:22 感谢由 471788hzsl 对此题目的解答所做出的贡献。这题最简单的方法就是看整个从C到X的路只有一条，所以排除c到x的概率1/2*1/2*1/2=1/8，就是A了
先算x是1/2*1/2*1/2，再用1-x的概率
wordy要你吗
这道题要用取反，从x口出的话是三个二分之一相乘，就是八分之一，从y就是八分之七
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2022-07-18 18:46:32
wordy要你吗回复wordy要你吗
用正解也行，比较麻烦
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2022-07-18 18:49:22
908373zz
救命，我咋没看到c在图里的哪
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2022-02-13 16:06:45
574190tuh回复908373zz
应该就是指的Z
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2022-05-09 11:17:17
304326uo
首先分为上下两条路线，下面都是到y就是50%。上面路线的其中一条通到y就是50%*50%=25%，上面路线的另一条又分为两条，其中一条道y就是25%*50%=12.5%。最后加在一起50%+25%+12.5%=87.5%
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2021-09-07 17:10:36
171763l
这题，其实看一下通往X的路只有一条，去Y的很多条，这个数字肯定要大于80%的，蒙个A正确率不会低
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2021-07-21 00:23:41
别骂了别骂了再骂就把人骂傻了
C到Y下面的第一条和第一条中途的弧线实际上是一条路线，因为没有新增的点，可以理解为拐了个弯绕回去了
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2020-03-11 20:09:44
Heyob
从C开始往下面那条线走，从Y出来，概率是1/2 从C开始往上走，只有两条路可以走到Y，一条是1/2*1/2，一条是1/2*1/2*1/2 ，三者相加，即是答案
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2019-12-08 20:40:10
Richie_
这题显然算X简单些 (1/2)^3=1/8 然后1-1/8=7/8 完事
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2019-08-01 09:00:34
我一定能杀g
为啥我数九条路啊
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2018-11-20 15:08:43
土拨鼠
从C出发抵达X或Y的总概率为1。 从C出发到达X的概率为1/2*1/2*1/2=1/8，因此从C出发到达Y的概率为1-1/8=7/8=87.5%
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2018-08-27 14:38:33
Dulaan
可以直接算，每个岔口分流时除以二，再把汇集到一起的相加。
0.5＋0.25＋0.125
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2018-07-28 21:27:54
发呆的夜之亡魂
我觉得是9条路吧，按照除以二除以二的做法就可以算出来了
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2018-07-19 11:33:32
默默
算路的总数与通往目的地的路数
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2018-06-19 09:17:26
Crystal
第一个解析，是什么原理喃？
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2017-11-22 14:08:23
JLKJLNK
每条路的可能性是1／2，所以y出口的可能性是1／2+1／2*1／2+1／2*1／2*1／2=87.5%
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2017-10-29 14:40:58
发呆的夜之亡魂回复JLKJLNK
我觉得你的才是正解
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2018-07-19 11:32:47
pig0524
为啥一共是八条啊？我觉得不止啊
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2016-10-15 23:28:06
WH-KYY回复pig0524
我觉得一共有9条路，从Y出来是8条，8/9也是选A
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2016-12-11 15:19:47
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