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【OG20-P601-735题】
A certain cultivated herb is one of a group of closely related plants that thrive in soil with high concentrations of metals that are toxic to most other plants. Agronomists studying the growth of this herb have discovered that it produces large amounts of histidine, an amino acid that, in test-tube solutions, renders these metals chemically inert. Hence, the herb’s high histidine production must be the key feature that allows it to grow in metal-rich soils.
In evaluating the argument, it would be most important to determine which of the following?
分析A选项
分析B选项
分析C选项
分析D选项
分析E选项
题型:评价题
答案:B
文章大意:一种特定的栽培药草是一组紧密相关的植物,它们在土壤中茁壮成长,而这些土壤中含有高浓度的金属,而这些金属对大多数其他植物都是有毒的。研究这种草药生长的农学家们发现,这种草药产生大量的histidine,这种氨基酸在试管溶液中,使这些金属在化学上是惰性的。因此,该草本植物的高histidine产量必须是使其在富含金属的土壤中生长的关键特性。
前提:cultivated herb 能生成large amount of H (H能抗毒)
结论:凭借H,cultivated herb 能存活于metal-rich削弱:倘若 most other plants 也能生成H 仍无法抗毒,那H就不是能抗毒的理由
增强:倘若这个H别的植物没有,那就是只有cultivated herb凭借H存活下来选项分析:
A 是否这种植物能在没有有毒金属的土壤中生长;无关,排
B 是否相关植物中的其他品种也产生了H;如果相关植物中没有产生H,但是它们也能在金属土壤中生长,说明H不起作用;反之H就起了关键作用;正确
C 是否这种植物的高H产生与其他某种氨基酸的异常低的产生相关联;其他氨基酸,跳出范畴,排
D 是否将这种植物在富含金属的土壤中种植,过些日子,减少了土壤中的金属含量;可能是和此植物吸收金属有关,而非H得影响,排
E 是否随着这种植物成熟,H的浓度下降了;H下降可能还是能保证使金属惰性,并不能说明是否H起了作用,排
271355uxi
能想到的解释就是文中没有提到h的浓度下降。就是h使得金属惰性,没说h的浓度会怎样
275476gao
谜底就在谜面中,one of a group B. 样本选择的代表性 C. histidine产生的原因,无关
ziqi
控制变量法
174634p
做题的没注意!!A certain cultivated herb is one of a group of closely related plants ;this herb研究对象是一个herb个体,而不是一个group--因此可能会出现样本代表性问题,还是不敏感对语义和强调重点
592070lyaq
我感觉d是over time又加了个不必要(题目没提过)的限制。
有名字
重点是讨论是不是h使草能在金属浓度高的土壤中存活,d变成吸收金属含量草活下来了,都没讲h
旮旮
注意题干描述related plants that thrive,that就近修饰+动词原形 显然修饰这一种族related plants,而结论中只用一种herb产生的h物质就推断整个related plant存活的原因显然是不妥的,样本不足;
目标750
因为植物产生大量的histidine----所以能够在重金属环境下茁壮成长(能不能在重金属环境中生长取决于能不能产生histidine,所以重点在于histidine,没有histidine那么这个植物就和其它植物一样是个废物,根本就不能在重金属土壤中存活) 带着重心找答案,选B
285452zdsb
一种特定的栽培药草是一组紧密相关的植物,它们在土壤中茁壮成长,而这些土壤中含有高浓度的金属,而这些金属对大多数其他植物都是有毒的。研究这种草药生长的农学家们发现,这种草药产生大量的histidine,这种氨基酸在试管溶液中,使这些金属在化学上是惰性的。因此,该草本植物的高histidine产量必须是使其在富含金属的土壤中生长的关键特性。
In evaluating the argument, it would be most important to determine which of the following?
在评估这个论证时,最重要的是确定下列哪一个?
评价题
A 是否这种植物能在没有有毒金属的土壤中生长;无关,排
B 是否相关植物中的其他品种也产生了H;如果相关植物中没有产生H,但是它们也能在金属土壤中生长,说明H不起作用;反之H就起了关键作用;正确
C 是否这种植物的高H产生与其他某种氨基酸的异常低的产生相关联;其他氨基酸,跳出范畴,排
D 是否将这种植物在富含金属的土壤中种植,过些日子,减少了土壤中的金属含量;可能是和此植物吸收金属有关,而非H得影响,排
E 是否随着这种植物成熟,H的浓度下降了;H下降可能还是能保证使金属惰性,并不能说明是否H起了作用,排
254431gpl
对比cultivated herb 抗毒性 和 most other plants不抗毒性 前提:cultivated herb 能生成large amount of H (H能抗毒) 結論:凭借H,cultivated herb 能存活于metal-rich evaluation双向逻辑 削弱:倘若 most other plants 也能生成H 仍无法抗毒,那H就不是能抗毒的理由 增强:倘若这个H别的植物没有,那就是只有cultivated herb凭借H存活下来
GMAT的大师兄
一种种植植物可以在对于其他植物有毒的高金属环境下生存。农学家发现这种植物产生大量的组氨酸 –一种氨基酸– 可以将这些金属化学物质变成惰性。因此,这种植物中的组氨酸一定是允许它在丰富金属土壤中生长的主要原因。 A选项:是否这种植物能够生长在没有有毒高金属的环境下 – (无关选项,这跟组氨酸的释放没有关系) B选项:是否其他相近植物也产生大量的组氨酸 (如果这些植物没有产生组氨酸但也可以在金属土壤中生长,那么说明这种植物在金属土壤中生长与组氨酸没有关系;反之说明组氨酸起了关键作用;正确) C选项:是否这种植物中组氨酸的大量生产是跟其他氨基酸的低生产有关系 (无关选项) D选项: 是否这种生长在高度金属环境下的植物会减少在土壤中金属的浓度 E选项.是否组氨酸的密集程度会随着植物的成熟而减少 (无关选项)
528893liuzu
我觉得把B选项理解成类比会容易好理解一点。这个是解释型文章,结果:herb能在金属地上生存,原因:the herb产生了H这种物质,只要选项能够对原因造成影响,就是正确的。the herb来自于closely related plants,那就说明这些plants跟herb有极高的相似性,所以如果这些plants跟herb一样能产生H这种物质,就加强了结论(也即原因),这是用了举例:同因同果的论证方法。
Smellycatt
所以这题是统计枚举啊! a certain herb is one of a group of closely related plants 结论是 the herb's (这个herb的)high histidine must be the key feature 要评价到底是不是key feature 所以问样本是否具有代表性 是否others of related group of plants 也有histidine
杨淋清
可是选项B没有说能不能在金属土壤中生活,只说了会不会产生H啊?
Lynne123回复 杨淋清
我也觉得 万一他们也能在金属里生活呢
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2019-12-02 10:40:48
207869vzr回复杨淋清
题干已经说了能在含金属的土壤里存活了,那个plants后面的定语从句修饰的是plants,而不是herb
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2019-12-19 15:26:28
babyweezy
herb is one of the plant..背景李说明了子集的特征,就推出全集的结果,明显不妥。要说明分析全集的特征,才能推出全集的结果。
jojo1990回复babyweezy
我觉得这个答案才是正解,one of,others of
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2019-10-31 21:04:41
地狱恶犬冲啊回复babyweezy
但是它没有推出全集啊,结论不是说的make it吗
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2020-01-12 11:05:17
373961gg回复 地狱恶犬冲啊
第一句里的that是修饰plants这个合集的呀
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2020-08-01 06:48:19
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