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【OG20-P161-101题】
If m and p are positive integers and m2 + p2 < 100, what is the greatest possible value of mp ?
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M<10 且P<10 然后一个个数字试验
M=9 /8/7/6/5
可知 m=7
499685skw
多试几个数，不是=9就代表能得到最大值
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2022-09-26 22:05:17
313429e
两个未知数mp可以相等的吗 相等表达应该写成是m*m了
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2022-08-11 13:28:06
imdereck
hhhh, m²+p²≥2mp
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2021-10-25 20:53:54
570239pybw
看来你们是没学过均值不等式了
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2021-02-16 10:03:47
emily666
OG也是一个个去试
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2020-04-02 17:03:44
GMAT必定上700
100＞m²+p²≥2mp， 也就是100＞2mp，得出mp＜50，最大的就是49
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2019-04-04 15:55:52
567464a回复GMAT必定上700
为什么m²+p²≥2mp呢？
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2021-01-22 11:01:05
567464a回复 567464a
首先x²≥0。
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2021-01-23 16:51:46
Kaz的琳琳宝贝回复 567464a
(m-p)^2≥0
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2021-10-05 11:37:53
730以上
试答案，题目问最大，先51，分解质因数，3、17.不符合前提；下一个49，符合。
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2018-01-22 22:27:26
Naomi回复730以上
49=7x7 那m和p不就相等了么，不明白哎
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2018-03-16 22:35:30
撒哈拉瓜兔回复 Naomi
沒說mp不能相等呀
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2018-07-04 22:42:51
许吞吞回复 Naomi
可以平方（m^2+p^2）两边都平方的话，把mp挪到一边，可以求出mp的乘积要小于50，所以可以取的最大值是49
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2018-08-06 17:13:23
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