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【OG20-P168-139题】
If X is the hundredths digit in the decimal 0.1X and if Y is the thousandths digit in the decimal 0.02Y, where X and Y are nonzero digits, which of the following is closest to the greatest possible value of 0.1X0.02Y
分析A选项
分析B选项
分析C选项
分析D选项
分析E选项
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答案 C
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950267voay
太坑了吧，我还以为是0.1*X
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2021-12-01 20:30:13
Crystal8
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2021-11-22 13:27:13
1297678eu
谁能帮我翻译一下这个题
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2021-10-17 12:41:55
林老师啦
真尼玛坑爹啊 190/21≈9
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2021-05-12 22:51:49
emily666
题目都不难，但是时间压力下容易想不到思路
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2020-04-26 19:38:33
baoyuecao
这个好坑啊，看成乘法就真的没法做了...
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2019-07-10 10:33:38
锤子的爱情回复 baoyuecao
确实
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2021-01-21 20:32:50
VirDeer777
Y是1，X是9的时候分数最大。190/21=9.047.... 所以跟9最接近
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2019-06-07 00:32:51
乔治8198
这题有点陷阱的，因为小数点后面位数不是很多，所以不能简单地把0.19近似为0.2，把0.021近似为0.02，而是按照原值计算。
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2018-12-11 21:47:59
Xxxffll
为什么不是和10更近？
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2018-09-11 06:54:47
Yang1116回复Xxxffll
因为，离9更近...啊。
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2018-10-18 01:14:26
441420ztyf回复Xxxffll
9+1/21,和10差20/21，和9只差1/21，哪个更近
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2020-08-07 23:56:33
艾默
题目什么意思？๑•́₃•̀2伐开心
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2018-05-13 09:03:12
Piaowei1111
X是小数0.1*的百位数，Y是0.02*的千位数，取x的最大值9, y的最小值1. 0.19/0.021约等于9
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2018-01-16 11:12:29
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