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【OG20-P150-27题】
Set X consists of eight consecutive integers. Set Y consists of all the integers that result from adding 4 to each of the integers in set X and all the integers that result from subtracting 4 from each of the integers in set X. How many more integers are there in set Y than in set X ?
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分析B选项
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分析E选项
小的4个数分别加4就可以得到大的4个数
大的4个数分别减4就可以得到小的4个数
所以X所含的8个数Y都有,另外还会有8个数
例如:X={n,n+1,n+2,n+3,n+4,n+5,n+6,n+7},共8个数
Y={n-4,n-3,n-2,n-1,n,n+1,n+2,n+3,n+4,n+5,n+6,n+7,n+8,n+9, n+10,
n+11},共16个数
九粥
脑瓜疼 为啥审题这么粗心
Lori88
原来是多几个,一不留神看成Y有几个了
1056929catn
我看成了y有几个数...哎 原来是多几个。 审题要细心
emily666
看成了how much more... 无语
关关
集合中的数字可重复吗?
赤木青帝回复关关
亲测,不会重复
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2019-12-08 21:14:55
Stella05回复关关
会重复啊,怎么不重复?
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2020-03-09 21:22:00
中国人都是好样的回复关关
没有重复啊,有重复就不会是8了
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2022-10-05 14:08:24
164001cwdmh
这题问的好像是,Y集合比X集合多几个整数 ,就是个加减题啊,果然是想复杂了吗。。。。
emily666回复164001cwdmh
还以为多几个数字。。唉
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2020-04-22 15:29:28
Stella z
这题有重复的部分吧
不灭的凤凰
问题问的是多了几个。。。。。。。。。。。。。。
Ellerybaby
8个连续整数,加四前四位变成后四位,减四后四位变成前四位。所以一共多了4+4,8个不同的元素
YangZ回复Ellerybaby
thx
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2019-01-05 11:08:18
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