题库搜索>问题求解PS-17767
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Let n and k be positive integers with k≦n. From an n×n array of dots, a k×k array of dots is selected. The figure above shows two examples where the selected k×k array is enclosed in a square. How many pairs (n, k) are possible so that exactly 48 of the dots in the n×n array are NOT in the selected k×k array?
分析A选项
分析B选项
分析C选项
分析D选项
分析E选项
这里要缩小一下范围
n+k n-k加减对于奇偶性是没影响的,所以这两项同奇偶,因为相乘是48,所以不可能是两个奇数,所以是两个偶数,推出nk是同奇偶的。
但是48只有一个3,只可能是偶数×偶数,所以48分解之后的3肯定和一个2是在一起的,于是有三种可能性 2*24 6*8 4*12
再都带进去,三个二元方程组,都没问题
487126tr
n^2-k^2=48有几个解 将上式化为(n+k)(n-k)=48 排除48的奇数因子,有48=2*24=4*12=6*8 每个都可以带入,所以有三对nk
371715hkenr
还是要把48先拆分到质因数乘积,不然列举真的容易漏数。 。
196309fxht
(n - k) * (n + k) = 48 计算48可以分解成多少个2数相乘的组合,48 因数分解:(2,2,2,2,3),可以分解成多少个两数相乘 (2,24), (4,12), (8,6), (16,3) 小的数=n-k,大的数=n+k,因为n-k+n+k=2n,n是整数,所以两数的和只能是偶数,去掉(16,3) 的组合,剩下3组。
Crystal8
看错了题目(题目意思理解错误),在n*n内但不在k*k内,所以就是两者相减啊!!!(脑子好混乱啊,太久没练了
iamChloe
6和8 怎么可以啊 n+k=8 n-k=6 算出来n<k,题目都不成立啊
iamChloe回复 iamChloe
对不起 请无视 是我算错了
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2021-09-11 16:01:51
DavidMao
NOT! NOT!
贾思敏
n^2-k^2=48 (n+k)(n-k)=48 48=2*2*2*2*3 所以有组合(2*24),(4*12),(8*6),(16*3),(48*1) 又因为n^2和k^2奇偶性不变,n^2-k^2=48 里面n^2和k^2要为同奇同偶则为偶,所以(16*3),(48*1) 排除
1493908ix
n^2-k^2=48 (n+k)(n-k)=48 48=2*2*2*2*3 所以有组合(2*24),(4*12),(8*6),(16*3),(48*1) 又因为nk必须为整数,排除(16*3),(48*1)
chicaicai
竟然忽略了同奇数同偶
C韵
如图可知,n²-k²=48 → (n+k)(n-k)=48 48=1*48=2*24=3*16=4*12=6*8 两个数相乘偶,则两个数均为偶或一奇一偶,但又因两个数由n、k加减所得所以只能同为偶 因此排除1*48,3*16,剩下3种组合
ytt
即,求n2 - K2 = 48=> (49,1), (64,16), (169,121). Alternatively, 把48拆出所有的factors. (13,11)这一组真的很容易漏掉 衰
leeleeleee
看见这个图!!就想起平方差公式 a2-b2=(a+b)(a-b)。 为啥想到,咱也不敢问。 找一找是谁乘一乘能得48,1/48,2/24,3/16,4/12,6/8.(n+k>n-k) 带进公式里瞅一瞅,谁能成立呢,嘻嘻
Thomasgo回复 leeleeleee
整天嘻嘻嘻,负赞!
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2019-10-31 09:39:10
我要上700!!回复 leeleeleee
难题300 全看你的解析了 感谢!
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2020-10-22 20:03:35
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