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A circular rim 28 inches in diameter rotates the same number of inches per second as a circular rim 35 inches in diameter. If the smaller rim makes x revolutions per second, how many revolutions per minute does the larger rim make in terms of x?
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题干：一个直径28英寸的圆环每秒旋转的英寸数与一个直径35英寸的圆环每秒旋转的英寸数相同。小的每秒转x圈，问大的每分钟转多少圈。
解析：第一句话的意思是大小两圆环转速相同。因为小的每秒转x圈，求出转速：每秒28πx英寸。用转速除以大的周长得每秒大的转几圈：28πx/35π。由此可求每分钟~
小良冠二郎
per minute...
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2023-05-22 18:48:03
啊啊我想读书
小圈直径28，大圈直径35，两个圈每秒转的总长一样。小圈每秒X圈，设大圈每秒转动y圈。在同样时间里，大圈小圈走的路程相等，2π*14*x=2π*17.5*y，求出Y=4X/5。也就是大圈Y每走一圈，小圈X走4/5圈。大圈一分钟走的路程是60Y，用X表示为60y=（4X/5）*60=48X
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2022-10-31 22:15:15
wordy要你吗
应该是x*28Π＝35Πv，v指大轮每秒转几圈，这个v乘上60即可
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2022-07-18 13:07:35
贾思敏
pace慢的题1反思：理解这句话有点慢- If the smaller rim makes x revolutions per second, how many revolutions per minute does the larger rim make in terms of x? 速度=圆的周长*revolution的数量，问大的速度的revolution是多少？（in/h） 小的速度为v1=28πx （in/s） 当t=1s时，小的路程为 28πx （in） 所以大的revolutions，也就是可以说是大的速度（in/h）是 [28πx/(35π)]*60=48π
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2021-10-07 11:42:46
William(GMAT 750+)
转速相同，不是转的圈数相同
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2021-03-06 19:00:07
Go800
注意审题：28π为周长，每秒转x圈，所以28πX=35πY。求出Y用X来表达，然后乘以60秒。
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2021-02-20 18:08:14
374542unoqh
每秒转化成每分钟乘以60
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2021-02-12 23:53:29
283900xfsak
题干中给出的条件为x转/秒 答案单位为y转/分钟 注意换算！
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2020-10-03 14:21:57
吴ws
这个对应什么考点诶，晕
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2020-07-31 21:13:06
ZiraoLi
这道题怎么解呀？求助
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2020-07-18 21:02:25
carpe diem
注意读题！题目中给出的每秒转多少圈，而最后问的是每分钟
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2019-11-27 23:11:42
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A circular rim 28 inches in diameter rotates the same number of inches per second as a circular rim 35 inches in diameter. If the smaller rim makes x revolutions per second, how many revolutions per minute does the larger rim make in terms of x?
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